AMC 10 · 2011 · #6
Easy mode Grade 5Casper starts with a bag of candies. On the first day he eats 31 of them, then gives 2 candies to his brother.
On the second day he eats 31 of what is left, then gives 4 candies to his sister. On the third day he eats his last 8 candies.
How many candies did Casper have at the start?
Pick an answer.
AMC 10 2011 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Try it yourself first — the explanation is most useful after you’ve attempted it.
Toolkit + CCSS Solution
Understand
Restated: Casper starts with some candies. Day 1: he eats $\frac{1}{3}$ of them, then gives $2$ away. Day 2: he eats $\frac{1}{3}$ of what is left, then gives $4$ away. Day 3: he eats his last $8$ candies. Find how many he had at the very start.
Givens: Each day he eats $\frac{1}{3}$ of the candies he has at the start of that day; After eating on Day 1 he gives away $2$; after eating on Day 2 he gives away $4$; On Day 3 exactly $8$ candies are left, and he eats all of them; Answer choices: (A) $30$, (B) $39$, (C) $48$, (D) $57$, (E) $66$
Unknowns: The number of candies Casper had at the beginning
Understand
Restated: Casper starts with some candies. Day 1: he eats $\frac{1}{3}$ of them, then gives $2$ away. Day 2: he eats $\frac{1}{3}$ of what is left, then gives $4$ away. Day 3: he eats his last $8$ candies. Find how many he had at the very start.
Givens: Each day he eats $\frac{1}{3}$ of the candies he has at the start of that day; After eating on Day 1 he gives away $2$; after eating on Day 2 he gives away $4$; On Day 3 exactly $8$ candies are left, and he eats all of them; Answer choices: (A) $30$, (B) $39$, (C) $48$, (D) $57$, (E) $66$
Plan
Primary tool: #11 Work Backwards
Secondary: #4 Introduce a Variable, #6 Guess and Check
The problem hands us the END of the story ($8$ candies left) and asks for the START, so Tool #11 (Work Backwards) is the natural fit: undo each action in reverse order. To undo a give-away we add the candies back; to undo eating $\frac{1}{3}$ we recover the whole from the $\frac{2}{3}$ that remained. Tool #4 (Introduce a Variable) offers a forward equation as a cross-check, and Tool #6 (Guess and Check) lets us confirm the recovered start by running the story forward or by testing a choice.
Execute — Answer: A
4.OA.A.3 Step 1 Undo the last give-away
- Read the story from the end.
- On Day 3 Casper eats his final $8$ candies, so he had $8$ at the start of Day 3.
- Those $8$ are what was left after he gave $4$ to his sister on Day 2.
- Undoing that gift means putting the $4$ back: before the gift he had $8 + 4 = 12$.
- So right after he finished eating on Day 2, he had $12$ candies.
💡 To reverse giving candies away, hand them back.
5.NF.A.2 Step 2 See what fraction survives eating
- Each day Casper eats $\frac{1}{3}$ of that day's candies.
- Whatever he does not eat stays, and the part that stays is $1 - \frac{1}{3} = \frac{2}{3}$.
- So the $12$ candies left after eating on Day 2 are exactly $\frac{2}{3}$ of the number he had at the start of Day 2.
- That link between $\frac{2}{3}$ and $12$ is the key we will use to step backward through each eating.
💡 Eating one third always leaves two thirds behind.
5.NF.B.6 Step 3 Recover each day's starting amount
- If $\frac{2}{3}$ of a day's candies equals $12$, then $\frac{1}{3}$ of them is half of $12$, which is $6$, so the whole ($\frac{3}{3}$) is $3 \times 6 = 18$.
- Casper began Day 2 with $18$ candies.
- Those $18$ are what was left after he gave $2$ to his brother on Day 1, so before that gift he had $18 + 2 = 20$.
- Now $20$ is $\frac{2}{3}$ of his original pile: $\frac{1}{3}$ is half of $20$, which is $10$, so the whole start is $3 \times 10 = 30$.
- Casper began with $30$ candies, which is choice (A).
💡 Knowing two thirds of a pile lets you rebuild the whole pile.
4.OA.A.3 Step 4 Check by running the story forward
- Test the recovered start of $30$ by playing the story forward.
- Day 1: eat $\frac{1}{3}$ of $30 = 10$, leaving $20$; give $2$ away, leaving $18$.
- Day 2: eat $\frac{1}{3}$ of $18 = 6$, leaving $12$; give $4$ away, leaving $8$.
- Day 3: eat the final $8$.
- Everything matches the problem exactly, so $30$ is correct.
💡 A start that replays into the exact ending must be the right start.
4.OA.A.3 Read the story from the end. On Day 3 Casper eats his final $8$ candies, so he h 5.NF.A.2 Each day Casper eats $\frac{1}{3}$ of that day's candies. Whatever he does not e 5.NF.B.6 If $\frac{2}{3}$ of a day's candies equals $12$, then $\frac{1}{3}$ of them is h 4.OA.A.3 Test the recovered start of $30$ by playing the story forward. Day 1: eat $\frac Review
Reasonableness: The forward replay lands on $0$ candies after Day 3 with the right amounts left at every stage ($20$, $18$, $12$, $8$), so the answer $30$ is consistent with the whole story. It is also the smallest choice, which fits a shrinking pile that must stay a multiple of $3$ before each eating. Bigger choices like $66$ would leave far more than $8$ at the end.
Alternative: Set up a forward equation with a variable. Let $x$ be the start. After Day 1: $\frac{2}{3}x - 2$. After Day 2 eating: $\frac{2}{3}\left(\frac{2}{3}x - 2\right)$, then $-4$ leaves the final $8$: $\frac{2}{3}\left(\frac{2}{3}x - 2\right) - 4 = 8$. Solving gives $\frac{2}{3}x - 2 = 18$, so $\frac{2}{3}x = 20$ and $x = 30$. You could also just test the choices; only $30$ replays to exactly $8$ candies on Day 3.
CCSS standards used (min grade 5)
4.OA.A.3Solve multi-step word problems using four operations with whole numbers (Undoing each give-away by adding candies back ($8+4=12$, $18+2=20$) and replaying the story forward to check the answer.)5.NF.A.2Solve word problems involving addition and subtraction of fractions (Finding the fraction that survives eating: $1 - \frac{1}{3} = \frac{2}{3}$ remains each day.)5.NF.B.6Solve real-world problems involving multiplication of fractions and mixed numbers (Recovering each day's whole amount from the $\frac{2}{3}$ that remained ($\frac{2}{3}$ of the pile $=12 \Rightarrow 18$, and $=20 \Rightarrow 30$).)
⭐ Start from the end and undo each move: add back what was given away, and rebuild the whole pile from the two thirds that were left.
⭐ Start from the end and undo each move: add back what was given away, and rebuild the whole pile from the two thirds that were left.
More like this
Same problem type. Tags show what each one shares with this problem.
- AMC 10 2002A #6 Gr 5Similar levelSame sub-type: Successive Multiplicative StepsSame techniqueWork Backwards
Cindy was asked by her teacher to subtract 3 from a certain number and then divide the result by 9. Instead, she subtrac…
- AMC 10 2005B #3 Gr 5Similar levelSame sub-type: Successive Multiplicative StepsUsesComplementary Counting Identify Subproblems
A gallon of paint is used to paint a room. One third of the paint is used on the first day. On the second day, one third…
- AMC 10 2014A #3 Gr 5Similar levelSame sub-type: Successive Multiplicative StepsUsesDimensional Analysis Identify Subproblems
Bridget bakes 48 loaves of bread for her bakery. She sells half of them in the morning for textdollar 2.50 each. In the…