AMC 8 · 2015 · #12

Easy mode Grade 4
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Problem

Picture a cube. A cube has 1212 edges in total.

Two edges are a "parallel pair" if they point in the same direction and never touch each other. For example, in the figure, AB\overline{AB} and GH\overline{GH} are a parallel pair, and so are EH\overline{EH} and FG\overline{FG}.

How many different parallel pairs of edges does the cube have?

(A) 6(B) 12(C) 18(D) 24(E) 36\textbf{(A) }6\qquad\textbf{(B) }12\qquad\textbf{(C) }18\qquad\textbf{(D) }24\qquad \textbf{(E) }36

Pick an answer.

(A)
6
(B)
12
(C)
18
(D)
24
(E)
36
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Toolkit + CCSS Solution

Understand

Restated: A cube has $12$ edges. Count how many unordered pairs of those edges are parallel to each other — pairs like $\overline{AB}$ and $\overline{GH}$, or $\overline{EH}$ and $\overline{FG}$.

Givens: The shape is a cube, with $12$ edges total; Two edges count as a "parallel pair" if they point in the same direction (or exactly opposite); Pairs are unordered: $\{e_1, e_2\}$ is the same pair as $\{e_2, e_1\}$; Answer choices: (A) $6$, (B) $12$, (C) $18$, (D) $24$, (E) $36$

Unknowns: The total number of unordered parallel-edge pairs on the cube

Understand

Restated: A cube has $12$ edges. Count how many unordered pairs of those edges are parallel to each other — pairs like $\overline{AB}$ and $\overline{GH}$, or $\overline{EH}$ and $\overline{FG}$.

Givens: The shape is a cube, with $12$ edges total; Two edges count as a "parallel pair" if they point in the same direction (or exactly opposite); Pairs are unordered: $\{e_1, e_2\}$ is the same pair as $\{e_2, e_1\}$; Answer choices: (A) $6$, (B) $12$, (C) $18$, (D) $24$, (E) $36$

Plan

Primary tool: #7 Identify Subproblems

Secondary: #10 Create a Physical Representation, #2 Make a Systematic List

Trying to scan all $12$ edges and check every pair would mean checking $66$ pairs — too many to do safely by eye. Tool #10 (Physical Representation) helps first: pick up any box or cube and look at it. The $12$ edges fall into exactly $3$ directions (length, width, height), with $4$ parallel edges in each direction. Tool #7 (Identify Subproblems) turns the big count into three identical mini-counts: "how many pairs from $4$ edges?" Tool #2 (Systematic List) handles each mini-count by listing the pairs in order, so we never double-count or miss one. Add the three mini-counts and we're done.

Execute — Answer: C

#10 Create a Physical Representation 4.G.A.1 Step 1
  • Pick up a tissue box or any cube-shaped object and look at its $12$ edges.
  • They sort into $3$ directions: $4$ edges run left–right, $4$ run front–back, and $4$ run up–down.
  • Edges in the same direction are parallel; edges in different directions are not.
  • So the $12$ edges split cleanly into $3$ groups of $4$.
$$12 \text{ edges} = 3 \text{ directions} \times 4 \text{ edges per direction}$$

💡 Touching the cube makes the three directions obvious — and "same direction" is exactly what "parallel" means.

#7 Identify Subproblems 4.OA.A.3 Step 2
  • Now treat one direction at a time as its own little problem.
  • The question "how many parallel pairs total?" becomes three copies of "how many pairs from $4$ edges?" plus a sum at the end.
$$\text{total pairs} = 3 \times (\text{pairs from one group of } 4)$$

💡 Splitting one hard count into three identical easy counts is the Tool #7 subproblems move.

#2 Make a Systematic List 4.OA.A.3 Step 3
  • List the pairs inside one group.
  • Label the $4$ edges in a single direction as $1, 2, 3, 4$ and list every unordered pair in order — pair the smallest with each bigger one, then the next smallest, and so on: $\{1,2\}, \{1,3\}, \{1,4\}, \{2,3\}, \{2,4\}, \{3,4\}$.
  • That's $6$ pairs, and the ordering rule guarantees no repeats and no misses.
$$\{1,2\}, \{1,3\}, \{1,4\}, \{2,3\}, \{2,4\}, \{3,4\} \;\Rightarrow\; 6 \text{ pairs}$$

💡 A systematic list with a clear ordering rule is the safest way to count pairs without double-counting.

#7 Identify Subproblems 3.OA.A.1 Step 4
  • Each of the $3$ directions contributes the same $6$ pairs, and a pair from one direction cannot equal a pair from another (the edges point different ways).
  • So the total is $3$ groups of $6$ pairs.
$$3 \times 6 = 18 \;\Rightarrow\; \textbf{(C)}$$

💡 "$3$ groups of $6$" is exactly what multiplication means in Grade 3.

[1] #10 4.G.A.1 Pick up a tissue box or any cube-shaped object and look at its $12$ edges. They
[2] #7 4.OA.A.3 Now treat one direction at a time as its own little problem. The question "how m
[3] #2 4.OA.A.3 List the pairs inside one group. Label the $4$ edges in a single direction as $1
[4] #7 3.OA.A.1 Each of the $3$ directions contributes the same $6$ pairs, and a pair from one d

Review

Reasonableness: Sanity check by counting differently. The $12$ edges form $66$ unordered pairs in all ($12 \times 11 / 2 = 66$). Of those, the parallel ones are $18$, the perpendicular ones (edges in two different directions) are $3 \times (4 \times 4) = 48$, and $18 + 48 = 66$. The bookkeeping closes, so $18$ is consistent. Also: $18$ sits squarely between the small answers ($6, 12$) and the inflated traps ($24, 36$). Choice (D) $24$ is what you get if you accidentally treat $(e_1, e_2)$ and $(e_2, e_1)$ as different pairs in $2$ groups; choice (E) $36$ does it for all three groups. Choice (A) $6$ counts only one group, and (B) $12$ confuses pairs with edges.

Alternative: Tool #1 (Draw a Diagram) gives a face-by-face version. A cube has $3$ pairs of opposite (parallel) faces. Each pair of opposite faces shares $4$ parallel edges going around them, contributing $\binom{4}{2} = 6$ parallel pairs in that direction. With $3$ direction-pairs of faces, total $= 3 \times 6 = 18$. Same answer, drawn instead of touched.

CCSS standards used (min grade 4)

  • 3.OA.A.1 Interpret products of whole numbers (e.g., $5 \times 7$ as $5$ groups of $7$) (Reading $3 \times 6 = 18$ as "$3$ groups of $6$ pairs" when combining the three directional groups into the final total.)
  • 4.G.A.1 Draw and identify points, lines, line segments, rays, angles, perpendicular and parallel lines in two-dimensional figures (Recognizing that two edges are parallel exactly when they point in the same direction — and sorting the cube's $12$ edges into the three directional groups based on that property.)
  • 4.OA.A.3 Solve multistep word problems using the four operations (Splitting the count into three identical subproblems (one per direction), listing the $6$ pairs inside one group, and combining the partial results into one total.)

⭐ Pick up a box and look at its edges — they only point in $3$ directions, so the cube problem is really just "$6$ pairs, three times" — pure Grade 3 multiplication!

⭐ Pick up a box and look at its edges — they only point in $3$ directions, so the cube problem is really just "$6$ pairs, three times" — pure Grade 3 multiplication!