AMC 8 · 2017 · #6

Easy mode Grade 8

Problem

Picture a triangle. It has three angles inside it.

The three angles are in the ratio $3 : 3 : 4$ . That means if you split the total angle measure into $3 + 3 + 4 = 10$ equal parts, the angles take $3$ parts, $3$ parts, and $4$ parts.

The three angles inside any triangle always add up to $180$ degrees.

How many degrees is the largest angle?

$\textbf{(A) }18\qquad\textbf{(B) }36\qquad\textbf{(C) }60\qquad\textbf{(D) }72\qquad\textbf{(E) }90$

Pick an answer.

(A)

(B)

(C)

(D)

(E)

View mode:

Toolkit + CCSS Solution

Understand

Restated: A triangle has three interior angles whose measures are in the ratio $3:3:4$. Find the degree measure of the largest of those three angles.

Givens: The three interior angles of a triangle are in the ratio $3:3:4$; The sum of the interior angles of any triangle is $180^\circ$; Answer choices: (A) $18$, (B) $36$, (C) $60$, (D) $72$, (E) $90$ (degrees)

Unknowns: The degree measure of the largest of the three angles

Understand

Restated: A triangle has three interior angles whose measures are in the ratio $3:3:4$. Find the degree measure of the largest of those three angles.

Plan

Primary tool: #7 Identify Subproblems

Secondary: #3 Eliminate Possibilities

Tool #7 (Identify Subproblems) splits the question into two clean pieces: (a) figure out how many degrees one "ratio unit" is worth, then (b) use that unit to size the largest angle. The ratio $3:3:4$ contains $3+3+4=10$ equal units total, and those $10$ units must share the $180^\circ$ of a triangle — so one unit is just $180^\circ \div 10$. Once we know one unit, the largest angle (the $4$-unit part) is immediate. Tool #3 (Eliminate Possibilities) is the back-up check: since this is multiple choice, every candidate answer should be at most $180^\circ$ and should be expressible as $4$ copies of an integer share, which quickly rules out most options.

Execute — Answer: D

#7 Identify Subproblems 3.OA.D.8 Step 1

Add the parts of the ratio to see how many equal shares the $180^\circ$ gets split into.
The ratio $3:3:4$ has $3+3+4=10$ parts in total.

$$3 + 3 + 4 = 10 \text{ parts}$$

💡 Counting up the pieces of a ratio is a one-step addition word problem from Grade 3.

#7 Identify Subproblems 8.G.A.5 Step 2

Use the fact that the three interior angles of any triangle sum to $180^\circ$.
So those $10$ equal shares fit exactly inside $180^\circ$, and one share is found by dividing.

$$180^\circ \div 10 = 18^\circ \text{ per share}$$

💡 Knowing that a triangle's interior angles always add to $180^\circ$ is the Grade 8 informal angle-sum fact.

#7 Identify Subproblems 4.OA.A.2 Step 3

The largest angle is the $4$-share part of the ratio, so multiply one share by $4$ to get its measure in degrees.

$$4 \times 18^\circ = 72^\circ \;\Rightarrow\; \textbf{(D)}$$

💡 "$4$ copies of a share" is exactly the multiplicative-comparison move from Grade 4.

#3 Eliminate Possibilities 4.MD.C.7 Step 4

Verify by adding the three angles back together, using the ratio: $3$ shares + $3$ shares + $4$ shares should equal $180^\circ$.
This rules out every other multiple-choice candidate.

$$54^\circ + 54^\circ + 72^\circ = 180^\circ \;\checkmark$$

💡 Adding angle parts to check that they make the whole is exactly the Grade 4 "angle measure is additive" idea.

[1] #7 3.OA.D.8 Add the parts of the ratio to see how many equal shares the $180^\circ$ gets spl

[2] #7 8.G.A.5 Use the fact that the three interior angles of any triangle sum to $180^\circ$.

[3] #7 4.OA.A.2 The largest angle is the $4$-share part of the ratio, so multiply one share by $

[4] #3 4.MD.C.7 Verify by adding the three angles back together, using the ratio: $3$ shares + $

Review

Reasonableness: The three angles work out to $54^\circ, 54^\circ, 72^\circ$ — all positive, all less than $180^\circ$, and summing to exactly $180^\circ$. The triangle is isosceles (two equal small angles) with one slightly larger angle, which matches the $3:3:4$ ratio (the largest is just a bit bigger than the other two, not dramatically so). The largest angle $72^\circ$ is less than $90^\circ$, so this is an acute triangle — consistent with the modest $3:3:4$ ratio. Answer (D) $72^\circ$ is the right size.

Alternative: Tool #6 (Guess and Check) on the answer choices: the largest angle must be exactly $\tfrac{4}{10} = \tfrac{2}{5}$ of $180^\circ$. Quickly compute $\tfrac{2}{5} \times 180 = 72$ — only choice (D) matches. Alternatively check each option by dividing it by $4$ to find a candidate "share" and seeing whether $10$ shares give $180^\circ$: only $72 \div 4 = 18$ and $10 \times 18 = 180$ works.

CCSS standards used (min grade 8)

3.OA.D.8 Solve two-step word problems using four operations within 100 (Adding the ratio parts $3+3+4=10$ to count the total number of equal shares.)
8.G.A.5 Use informal arguments to establish facts about angle sum and exterior angles (Applying the triangle interior angle-sum fact ($180^\circ$) so the $10$ ratio shares can be matched to a known total.)
4.OA.A.2 Multiply or divide to solve word problems involving multiplicative comparison (Computing the largest angle as $4 \times 18^\circ = 72^\circ$ — "$4$ times as big as one share.")
4.MD.C.7 Recognize angle measure as additive and solve addition and subtraction problems (Verifying $54^\circ + 54^\circ + 72^\circ = 180^\circ$ by adding the three angle parts to the whole.)

⭐ This AMC 8 problem only needs the Grade 8 fact you already know — the three angles of a triangle always add up to $180^\circ$!

Problem

Toolkit + CCSS Solution

Understand

Plan

Execute — Answer: D

Review

CCSS standards used (min grade 8)

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