AMC 10 · 2017 · #4

Grade 7 arithmetic
fraction-arithmeticlinear-equations-two-var convert-to-algebraguess-and-check ↑ Prerequisites: linear-equations-two-var
📏 Short solution 💡 1 insight
Problem
Two nonzero real numbers x and y satisfy 3x+yx3y\frac{3x+y}{x-3y}=-2. Using only that fact, find the numerical value of the second expression x+3y3xy\frac{x+3y}{3x-y} and match it to one of the five choices.

Pick an answer.

(A)
-3
(B)
-1
(C)
1
(D)
2
(E)
3

AMC 10 2017 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Introduce a Variable

Tool #4 (Introduce a Variable): the given equation is a single relation between the two unknowns x and y. Clearing the fraction turns it into a plain linear equation, and solving that equation reveals how x and y are tied together. Once that tie is known, the target expression collapses to a number. Tool #6 (Guess and Check) lets us pick a concrete pair (x,y) that fits and read the answer directly. Tool #3 (Eliminate Possibilities) matches the result to the five choices.

1STEP 1

Clear the fraction

Since x-3y ≠ 0, multiply both sides by it to clear the fraction: 3x+y=-2(x-3y).

3x+yx3y\frac{3x+y}{x-3y}=-2 → 3x+y = -2(x-3y)
2STEP 2

Find how x and y relate

Expand and collect like terms: 3x+y=-2x+6y becomes 5x=5y, so x=y.

3x+y=-2x+6y → 5x=5y → x=y
3STEP 3

Substitute into the target

Put x=y into x+3y3xy\frac{x+3y}{3x-y}: it becomes 4y2y\frac{4y}{2y}, and since y ≠ 0 the y cancels to 2.

x+3y3xy\frac{x+3y}{3x-y}=y+3y3yy\frac{y+3y}{3y-y}=4y2y\frac{4y}{2y}=2
4STEP 4

Match the choice

The target expression equals 2, which is choice (D).

x+3y3xy\frac{x+3y}{3x-y}=2 → (D)
Answer
2
Test a concrete pair. Take x=y=1: the given expression is 3(1)+113(1)\frac{3(1)+1}{1-3(1)}=42\frac{4}{-2}=-2, which matches the condition, and the target is 1+3(1)3(1)1\frac{1+3(1)}{3(1)-1}=42\frac{4}{2}=2. Trying x=y=2 gives the same target value 2, confirming the answer does not depend on the actual size of x and y, only on x=y.
💡Key takeaway

Clear the fraction first: 3x+yx3y\frac{3x+y}{x-3y}=-2 means 3x+y=-2(x-3y), which boils down to x=y, and then x+3y3xy\frac{x+3y}{3x-y}=4y2y\frac{4y}{2y}=2, choice (D).

  • Clear the fraction
  • Find how x and y relate
  • Substitute into the target
  • Match the choice