AMC 10 · 2024 · #8

Grade 6 rate-ratioalgebra
rateunit-conversionlinear-equations-one-var identify-subproblemsdimensional-analysis ↑ Prerequisites: fraction-arithmeticmulti-digit-arithmetic
📏 Medium solution 💡 3 insights

Problem

Amy, Bomani, Charlie, and Daria work in a chocolate factory. On Monday Amy, Bomani, and Charlie started working at 1:00 PM1:00 \ \mathrm{PM} and were able to pack 44, 33, and 33 packages, respectively, every 33 minutes. At some later time, Daria joined the group, and Daria was able to pack 55 packages every 44 minutes. Together, they finished packing 450450 packages at exactly 2:45 PM2:45\ \mathrm{PM}. At what time did Daria join the group?

(A) 1:25 PM(B) 1:35 PM(C) 1:45 PM(D) 1:55 PM(E) 2:05 PM\textbf{(A) }1:25\text{ PM}\qquad\textbf{(B) }1:35\text{ PM}\qquad\textbf{(C) }1:45\text{ PM}\qquad\textbf{(D) }1:55\text{ PM}\qquad\textbf{(E) }2:05\text{ PM}

Pick an answer.

(A)
$1:25 ext{ PM}$
(B)
$1:35 ext{ PM}$
(C)
$1:45 ext{ PM}$
(D)
$1:55 ext{ PM}$
(E)
$2:05 ext{ PM}$
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Toolkit + CCSS Solution

Understand

Restated: Amy, Bomani, and Charlie start packing at $1{:}00$ PM with rates of $4$, $3$, and $3$ packages every $3$ minutes. Daria joins later, packing $5$ packages every $4$ minutes. The group finishes $450$ packages at $2{:}45$ PM. At what time did Daria join?

Givens: Amy, Bomani, Charlie start at $1{:}00$ PM and pack $4$, $3$, $3$ packages per $3$ minutes; Daria's rate is $5$ packages per $4$ minutes; Group finishes $450$ packages at $2{:}45$ PM; Answer choices: (A) $1{:}25$ PM, (B) $1{:}35$ PM, (C) $1{:}45$ PM, (D) $1{:}55$ PM, (E) $2{:}05$ PM

Unknowns: The time Daria joined the group

Understand

Restated: Amy, Bomani, and Charlie start packing at $1{:}00$ PM with rates of $4$, $3$, and $3$ packages every $3$ minutes. Daria joins later, packing $5$ packages every $4$ minutes. The group finishes $450$ packages at $2{:}45$ PM. At what time did Daria join?

Givens: Amy, Bomani, Charlie start at $1{:}00$ PM and pack $4$, $3$, $3$ packages per $3$ minutes; Daria's rate is $5$ packages per $4$ minutes; Group finishes $450$ packages at $2{:}45$ PM; Answer choices: (A) $1{:}25$ PM, (B) $1{:}35$ PM, (C) $1{:}45$ PM, (D) $1{:}55$ PM, (E) $2{:}05$ PM

Plan

Primary tool: #7 Identify Subproblems

Secondary: #11 Work Backwards

The question hides two separate jobs: how much the first three workers pack across the whole shift, and how much Daria has to add on top to hit $450$. Tool #7 (Identify Subproblems) splits the work cleanly along those lines — combine the three rates, multiply by the full $105$ minutes, then subtract from $450$ to isolate Daria's contribution. Once we know how many packages Daria did, her rate tells us her working time. From there, Tool #11 (Work Backwards) is the natural finish: we know when she stopped ($2{:}45$ PM) and how long she worked, so we step backward to her start time.

Execute — Answer: A

#7 Identify Subproblems 6.RP.A.2 Step 1
  • Subproblem 1: combine the three steady rates.
  • Amy, Bomani, and Charlie all report their rates over the same $3$-minute window, so we can simply add the package counts.
$$\text{A+B+C rate} = 4 + 3 + 3 = 10 \text{ packages per } 3 \text{ minutes}$$

💡 Rates with the same time unit add directly — a Grade 6 unit-rate move.

#7 Identify Subproblems 6.RP.A.3 Step 2
  • Subproblem 2: count how many packages the first three pack across the entire shift.
  • The full work time is $2{:}45$ PM $- 1{:}00$ PM $= 1$ hour $45$ minutes $= 105$ minutes.
  • Split it into $3$-minute chunks: $105 \div 3 = 35$ chunks, each producing $10$ packages.
$$35 \times 10 = 350 \text{ packages by A, B, C}$$

💡 Once the rate sits at "$10$ per $3$ min," total work is just (number of chunks) $\times$ (packages per chunk).

#7 Identify Subproblems 4.OA.A.3 Step 3
  • Subproblem 3: use the $450$-package total to isolate Daria's contribution.
  • Whatever the first three did not pack, Daria must have packed.
$$\text{Daria's packages} = 450 - 350 = 100$$

💡 The total acts as a constraint — subtract the known piece to reveal the unknown piece.

#7 Identify Subproblems 6.RP.A.3 Step 4
  • Subproblem 4: convert Daria's package count into time using her rate.
  • Daria packs $5$ packages per $4$ minutes, so each package takes $\tfrac{4}{5}$ of a minute.
$$\text{Daria's time} = 100 \times \dfrac{4}{5} = 80 \text{ minutes}$$

💡 Multiplying by the reciprocal of the rate converts "how many packages" into "how many minutes" — the bread and butter of Grade 6 unit-rate work.

#11 Work Backwards 4.MD.A.2 Step 5
  • Work backwards from the finish to find Daria's start.
  • She stopped at $2{:}45$ PM and worked for $80$ minutes ($1$ hour $20$ minutes), so step that interval backward on the clock.
$$2{:}45 \text{ PM} - 1\text{h }20\text{min} = 1{:}45 \text{ PM} - 20 \text{ min} = 1{:}25 \text{ PM} \;\Rightarrow\; \textbf{(A)}$$

💡 Subtracting an elapsed time from an end time is a Grade 4 measurement skill — the same logic as a number line in reverse.

[1] #7 6.RP.A.2 Subproblem 1: combine the three steady rates. Amy, Bomani, and Charlie all repor
[2] #7 6.RP.A.3 Subproblem 2: count how many packages the first three pack across the entire shi
[3] #7 4.OA.A.3 Subproblem 3: use the $450$-package total to isolate Daria's contribution. Whate
[4] #7 6.RP.A.3 Subproblem 4: convert Daria's package count into time using her rate. Daria pack
[5] #11 4.MD.A.2 Work backwards from the finish to find Daria's start. She stopped at $2{:}45$ PM

Review

Reasonableness: Double-check by going forward from $1{:}25$ PM. Amy, Bomani, Charlie pack for $105$ minutes at $10$ per $3$ min $= 350$ packages. Daria works from $1{:}25$ PM to $2{:}45$ PM, which is $80$ minutes, at $5$ per $4$ min $= \tfrac{80}{4} \times 5 = 20 \times 5 = 100$ packages. Total: $350 + 100 = 450$. Matches the problem exactly, so $1{:}25$ PM is confirmed.

Alternative: Tool #3 (Eliminate Possibilities) on the answer choices: for each choice, compute Daria's working minutes (end time $-$ start time), translate into packages at $5$ per $4$ min, add the fixed $350$ packages from A+B+C, and keep only the choice that hits $450$. Choice (A) $1{:}25$ PM gives $80$ min $\Rightarrow 100$ packages $\Rightarrow 450$ total. Every other choice falls short, so (A) is the answer. This trades the cleaner algebra for a direct walk through the menu.

CCSS standards used (min grade 6)

  • 6.RP.A.2 Understand the concept of a unit rate $a/b$ associated with a ratio $a{:}b$ (Reading each worker's "packages per $3$ minutes" as a unit-rate-style ratio and combining the three rates over the shared $3$-minute window.)
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems (Scaling the combined rate $10$ packages per $3$ minutes up to $105$ minutes, and converting Daria's $100$ packages back into $80$ minutes via her $5$-per-$4$-minute rate.)
  • 4.OA.A.3 Solve multistep word problems with whole numbers and the four operations (Using the total of $450$ packages as a constraint to subtract the $350$ done by A, B, C and isolate Daria's $100$ packages.)
  • 4.MD.A.2 Use the four operations to solve word problems involving distances, time intervals, and money (Subtracting Daria's $80$-minute working span from the $2{:}45$ PM finish time to find her $1{:}25$ PM start time.)

⭐ Split the job — three workers cover the whole shift, Daria fills the gap — then rewind $80$ minutes from $2{:}45$ PM and the AMC 10 problem lands on a Grade 6 rate-and-clock question.

⭐ Split the job — three workers cover the whole shift, Daria fills the gap — then rewind $80$ minutes from $2{:}45$ PM and the AMC 10 problem lands on a Grade 6 rate-and-clock question.