AMC 8 · 2007 · #1

Grade 6 arithmetic
mean-median-mode-rangelinear-equations-one-varmulti-digit-arithmetic identify-subproblemsconvert-to-algebra ↑ Prerequisites: multi-digit-arithmeticmean-median-mode-range
📏 Short solution 💡 2 insights

Problem

Theresa's parents have agreed to buy her tickets to see her favorite band if she spends an average of 1010 hours per week helping around the house for 66 weeks. For the first 55 weeks she helps around the house for 88, 1111, 77, 1212 and 1010 hours. How many hours must she work for the final week to earn the tickets?

(A) 9(B) 10(C) 11(D) 12(E) 13\mathrm{(A)}\ 9 \qquad\mathrm{(B)}\ 10 \qquad\mathrm{(C)}\ 11 \qquad\mathrm{(D)}\ 12 \qquad\mathrm{(E)}\ 13

Pick an answer.

(A)
9
(B)
10
(C)
11
(D)
12
(E)
13
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Toolkit + CCSS Solution

Understand

Restated: Theresa needs to average $10$ hours of housework per week over $6$ weeks. In the first $5$ weeks she logs $8$, $11$, $7$, $12$, and $10$ hours. How many hours must she work in week $6$ to hit the $10$-hour average?

Givens: Target average over $6$ weeks: $10$ hours per week; First $5$ weekly hours: $8, 11, 7, 12, 10$; Answer choices: (A) $9$, (B) $10$, (C) $11$, (D) $12$, (E) $13$

Unknowns: The number of hours $x$ Theresa must work in week $6$

Understand

Restated: Theresa needs to average $10$ hours of housework per week over $6$ weeks. In the first $5$ weeks she logs $8$, $11$, $7$, $12$, and $10$ hours. How many hours must she work in week $6$ to hit the $10$-hour average?

Givens: Target average over $6$ weeks: $10$ hours per week; First $5$ weekly hours: $8, 11, 7, 12, 10$; Answer choices: (A) $9$, (B) $10$, (C) $11$, (D) $12$, (E) $13$

Plan

Primary tool: #3 Set Up an Equation

Secondary: #4 Introduce a Variable

The condition "average over $6$ weeks $= 10$" is a single equation about a single unknown — the week-$6$ hours. Tool #4 (Introduce a Variable) names that unknown $x$. Tool #3 (Set Up an Equation) turns the average rule (sum $\div$ count $=$ average) into $\dfrac{48+x}{6} = 10$. The cleanest shortcut is the equivalent form: total hours needed $=$ average $\times$ count $= 60$, so $x = 60 - 48$.

Execute — Answer: D

#4 Introduce a Variable 6.EE.A.2 Step 1
  • Name the unknown.
  • Let $x$ be the number of hours Theresa works in week $6$.
$$x = \text{hours in week } 6$$

💡 Giving the unknown a letter is the Grade 6 "write expressions with variables" move.

#3 Set Up an Equation 6.SP.B.5 Step 2
  • Convert the average condition into the total hours required.
  • Average $\times$ count $=$ sum, so the $6$-week total must equal $10 \times 6 = 60$ hours.
$$\text{total needed} = 10 \times 6 = 60$$

💡 The Grade 6 mean rule rearranges to total $=$ average $\times$ count. That turns "average $10$" into the hard number $60$.

#3 Set Up an Equation 4.NBT.B.4 Step 3

Add the first $5$ weeks to see how much Theresa has banked so far.

$$8 + 11 + 7 + 12 + 10 = 48$$

💡 Just a straight sum of the five known weeks.

#3 Set Up an Equation 6.EE.B.7 Step 4

The total must be $60$, and $48$ is already done, so week $6$ supplies the rest.

$$48 + x = 60 \;\Rightarrow\; x = 60 - 48 = 12 \;\Rightarrow\; \textbf{(D)}$$

💡 One-step linear equation: subtract $48$ from both sides.

[1] #4 6.EE.A.2 Name the unknown. Let $x$ be the number of hours Theresa works in week $6$.
[2] #3 6.SP.B.5 Convert the average condition into the total hours required. Average $\times$ co
[3] #3 4.NBT.B.4 Add the first $5$ weeks to see how much Theresa has banked so far.
[4] #3 6.EE.B.7 The total must be $60$, and $48$ is already done, so week $6$ supplies the rest.

Review

Reasonableness: Plug $x = 12$ back into the average: $\dfrac{8+11+7+12+10+12}{6} = \dfrac{60}{6} = 10$. The average lands exactly on $10$, matching the goal. Also, $12$ sits comfortably inside the existing weekly range ($7$ to $12$), so it is realistic — not a wild outlier.

Alternative: Tool #11 (Find an Invariant) via deviations from $10$: weeks $1$-$5$ deviate by $-2, +1, -3, +2, 0$, summing to $-2$. To make the total deviation zero (so the average is exactly $10$), week $6$ must contribute $+2$, giving $10 + 2 = 12$ hours. Same answer (D).

CCSS standards used (min grade 6)

  • 4.NBT.B.4 Fluently add and subtract multi-digit whole numbers (Adding $8 + 11 + 7 + 12 + 10 = 48$ and computing $60 - 48 = 12$.)
  • 6.EE.A.2 Write, read, and evaluate expressions in which letters stand for numbers (Naming the unknown week-$6$ hours with the variable $x$.)
  • 6.EE.B.7 Solve real-world problems by writing and solving equations of the form $x + p = q$ (Solving $48 + x = 60$ for $x$ in one step.)
  • 6.SP.B.5 Summarize numerical data sets, including reporting the number of observations and measures of center (Using average $\times$ count $=$ total to convert "average $10$ over $6$ weeks" into the total $60$.)

⭐ An average target is really a total target in disguise: multiply average by count to get the total you owe, subtract what you've already done, and the rest is week $6$.

⭐ An average target is really a total target in disguise: multiply average by count to get the total you owe, subtract what you've already done, and the rest is week $6$.