AMC 8 · 2010 · #21

Grade 6 arithmetic
fraction-arithmeticlinear-equations-one-varmulti-digit-arithmetic convert-to-algebraidentify-subproblems ↑ Prerequisites: fraction-arithmeticlinear-equations-one-var
📏 Long solution 💡 4 insights

Problem

Hui is an avid reader. She bought a copy of the best seller Math is Beautiful. On the first day, Hui read 1/51/5 of the pages plus 1212 more, and on the second day she read 1/41/4 of the remaining pages plus 1515 pages. On the third day she read 1/31/3 of the remaining pages plus 1818 pages. She then realized that there were only 6262 pages left to read, which she read the next day. How many pages are in this book?

Pick an answer.

(A)
120
(B)
180
(C)
240
(D)
300
(E)
360
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Toolkit + CCSS Solution

Understand

Restated: Hui reads the book over four days. On day $1$ she reads $\tfrac{1}{5}$ of the whole book plus $12$ more pages. On day $2$ she reads $\tfrac{1}{4}$ of what was left plus $15$ more. On day $3$ she reads $\tfrac{1}{3}$ of what was left plus $18$ more. After that there are $62$ pages left, which she finishes on day $4$. Find the total number of pages.

Givens: Day $1$: read $\tfrac{1}{5}$ of the total pages, plus $12$ extra; Day $2$: read $\tfrac{1}{4}$ of the remaining pages, plus $15$ extra; Day $3$: read $\tfrac{1}{3}$ of the remaining pages, plus $18$ extra; After day $3$, exactly $62$ pages remain (read on day $4$); Answer choices: (A) $120$, (B) $180$, (C) $240$, (D) $300$, (E) $360$

Unknowns: The total number of pages in the book

Understand

Restated: Hui reads the book over four days. On day $1$ she reads $\tfrac{1}{5}$ of the whole book plus $12$ more pages. On day $2$ she reads $\tfrac{1}{4}$ of what was left plus $15$ more. On day $3$ she reads $\tfrac{1}{3}$ of what was left plus $18$ more. After that there are $62$ pages left, which she finishes on day $4$. Find the total number of pages.

Givens: Day $1$: read $\tfrac{1}{5}$ of the total pages, plus $12$ extra; Day $2$: read $\tfrac{1}{4}$ of the remaining pages, plus $15$ extra; Day $3$: read $\tfrac{1}{3}$ of the remaining pages, plus $18$ extra; After day $3$, exactly $62$ pages remain (read on day $4$); Answer choices: (A) $120$, (B) $180$, (C) $240$, (D) $300$, (E) $360$

Plan

Primary tool: #11 Work Backwards

Secondary: #6 Guess and Check

The problem describes the book being eaten away day by day, and the last day's leftover ($62$ pages) is fully known. That is exactly when Tool #11 (Work Backwards) shines: start at the known end and undo each day in reverse. On each day, undoing has two clean moves — add back the "$+k$ extra pages" first, then recognize what's left as a known fraction of that morning's pile and scale up to find the pile. Tool #6 (Guess and Check) is kept as a backup: plug each of the five choices into the forward story and see which one ends with exactly $62$ pages left.

Execute — Answer: C

#11 Work Backwards 4.OA.A.3 Step 1
  • Start at the end.
  • After day $3$, exactly $62$ pages were left for day $4$.
  • Day $3$'s reading was "$\tfrac{1}{3}$ of the morning pile, plus $18$ more." Undo the $+18$ first: before those $18$ extra pages were read, day $3$ had $62 + 18 = 80$ pages still unread.
$$62 + 18 = 80 \text{ pages left after the } \tfrac{1}{3} \text{ chunk}$$

💡 Undoing a "$+18$" is just subtracting $18$ — a Grade 4 multi-step word-problem move.

#11 Work Backwards 6.RP.A.3 Step 2
  • Those $80$ pages are what was left after Hui read $\tfrac{1}{3}$ of day $3$'s morning pile, so $80$ is $\tfrac{2}{3}$ of that pile.
  • Scale up by $\tfrac{3}{2}$ to recover the full pile she faced on day $3$ morning.
$$80 \times \tfrac{3}{2} = 120 \text{ pages at the start of day } 3$$

💡 If a known fraction of a pile equals a known number, multiplying by the reciprocal gives the whole pile — Grade 6 ratio reasoning.

#11 Work Backwards 4.OA.A.3 Step 3
  • Now those $120$ pages are the leftover at the end of day $2$.
  • Day $2$'s reading was "$\tfrac{1}{4}$ of the morning pile, plus $15$ more." Add back the $15$ extra pages: $120 + 15 = 135$ pages were left right after the $\tfrac{1}{4}$ chunk.
$$120 + 15 = 135 \text{ pages left after the } \tfrac{1}{4} \text{ chunk}$$

💡 Same undoing trick as before — peel off the "$+15$" first, then handle the fraction.

#11 Work Backwards 6.RP.A.3 Step 4
  • Those $135$ pages are $\tfrac{3}{4}$ of day $2$'s morning pile (since Hui ate $\tfrac{1}{4}$ off the top).
  • Scale up by $\tfrac{4}{3}$ to find that pile, which is also what was left at the end of day $1$.
$$135 \times \tfrac{4}{3} = 180 \text{ pages at the start of day } 2$$

💡 Same Grade 6 ratio move: known part $\div$ known fraction $=$ whole pile.

#11 Work Backwards 6.RP.A.3 Step 5
  • Finally, $180$ pages is what was left after day $1$.
  • Day $1$'s reading was "$\tfrac{1}{5}$ of the whole book, plus $12$ more." Add back the $12$ extras: $180 + 12 = 192$ pages were left after just the $\tfrac{1}{5}$ chunk.
  • That $192$ is $\tfrac{4}{5}$ of the entire book.
  • Scale up by $\tfrac{5}{4}$ to get the total.
$$192 \times \tfrac{5}{4} = 240 \;\Rightarrow\; \textbf{(C)}$$

💡 One more Work-Backwards loop — undo $+12$, then scale $\tfrac{4}{5} \to 1$ — and the whole book pops out.

[1] #11 4.OA.A.3 Start at the end. After day $3$, exactly $62$ pages were left for day $4$. Day $
[2] #11 6.RP.A.3 Those $80$ pages are what was left after Hui read $\tfrac{1}{3}$ of day $3$'s mo
[3] #11 4.OA.A.3 Now those $120$ pages are the leftover at the end of day $2$. Day $2$'s reading
[4] #11 6.RP.A.3 Those $135$ pages are $\tfrac{3}{4}$ of day $2$'s morning pile (since Hui ate $\
[5] #11 6.RP.A.3 Finally, $180$ pages is what was left after day $1$. Day $1$'s reading was "$\tf

Review

Reasonableness: Run the story forward with $240$ pages to double-check. Day $1$: $\tfrac{1}{5} \times 240 + 12 = 48 + 12 = 60$ pages read, $180$ left. Day $2$: $\tfrac{1}{4} \times 180 + 15 = 45 + 15 = 60$ pages read, $120$ left. Day $3$: $\tfrac{1}{3} \times 120 + 18 = 40 + 18 = 58$ pages read, $62$ left. Day $4$: $62$. Total $= 60 + 60 + 58 + 62 = 240$. Everything lines up.

Alternative: Tool #6 (Guess and Check) directly on the choices. Try (A) $120$: day $1$ leaves $\tfrac{4}{5}(120) - 12 = 84$; day $2$ leaves $\tfrac{3}{4}(84) - 15 = 48$; day $3$ leaves $\tfrac{2}{3}(48) - 18 = 14 \neq 62$. Try (C) $240$: $\tfrac{4}{5}(240) - 12 = 180$; $\tfrac{3}{4}(180) - 15 = 120$; $\tfrac{2}{3}(120) - 18 = 62$. Match — answer is (C). The other choices miss $62$, confirming the result.

CCSS standards used (min grade 6)

  • 4.OA.A.3 Solve multi-step word problems with whole numbers (Undoing each day's "$+k$ extra pages" step — adding $18$, $15$, and $12$ back in turn to recover the pile size right after the fraction chunk.)
  • 5.NF.B.6 Solve real-world problems involving multiplication of fractions (Reading each day's $\tfrac{1}{n}$-of-remaining as a fraction of a pile and tracking how much is left after that fractional chunk is taken off the top.)
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems (Recovering each morning's pile from its leftover: $\tfrac{2}{3}$ pile $= 80 \Rightarrow$ pile $= 120$, $\tfrac{3}{4}$ pile $= 135 \Rightarrow$ pile $= 180$, and $\tfrac{4}{5}$ book $= 192 \Rightarrow$ book $= 240$.)

⭐ When a problem hands you the very last leftover, walk the story backwards — undo the "$+$ extras" first, then scale the fraction up to the whole pile. This AMC 8 question only needs Grade 6 ratio reasoning to crack.

⭐ When a problem hands you the very last leftover, walk the story backwards — undo the "$+$ extras" first, then scale the fraction up to the whole pile. This AMC 8 question only needs Grade 6 ratio reasoning to crack.