AMC 8 · 2022 · #2

Grade 6 arithmetic
function-evaluationorder-of-operationsformula-substitution identify-subproblems ↑ Prerequisites: order-of-operationsexponents
📏 Short solution 💡 1 insight

Problem

Consider these two operations:
\begin{align*} a , \blacklozenge , b &= a^2 - b^2\ a , \bigstar , b &= (a - b)^2 \end{align*}
What is the output of (53)6?(5 \, \blacklozenge \, 3) \, \bigstar \, 6?

(A) 20(B) 4(C) 16(D) 100(E) 220\textbf{(A) } {-}20 \qquad \textbf{(B) } 4 \qquad \textbf{(C) } 16 \qquad \textbf{(D) } 100 \qquad \textbf{(E) } 220

Pick an answer.

(A)
${-}20$
(B)
4
(C)
16
(D)
100
(E)
220
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Toolkit + CCSS Solution

Understand

Restated: Two brand-new operations are defined: $a \, \blacklozenge \, b = a^2 - b^2$ and $a \, \bigstar \, b = (a-b)^2$. They behave like functions that take two numbers as inputs. The task is to evaluate $(5 \, \blacklozenge \, 3) \, \bigstar \, 6$, doing the inner operation first because of the parentheses.

Givens: Rule 1: $a \, \blacklozenge \, b = a^2 - b^2$; Rule 2: $a \, \bigstar \, b = (a-b)^2$; Expression to evaluate: $(5 \, \blacklozenge \, 3) \, \bigstar \, 6$; Answer choices: (A) $-20$, (B) $4$, (C) $16$, (D) $100$, (E) $220$

Unknowns: The numerical value of $(5 \, \blacklozenge \, 3) \, \bigstar \, 6$

Understand

Restated: Two brand-new operations are defined: $a \, \blacklozenge \, b = a^2 - b^2$ and $a \, \bigstar \, b = (a-b)^2$. They behave like functions that take two numbers as inputs. The task is to evaluate $(5 \, \blacklozenge \, 3) \, \bigstar \, 6$, doing the inner operation first because of the parentheses.

Givens: Rule 1: $a \, \blacklozenge \, b = a^2 - b^2$; Rule 2: $a \, \bigstar \, b = (a-b)^2$; Expression to evaluate: $(5 \, \blacklozenge \, 3) \, \bigstar \, 6$; Answer choices: (A) $-20$, (B) $4$, (C) $16$, (D) $100$, (E) $220$

Plan

Primary tool: #7 Identify Subproblems

Secondary: #3 Eliminate Possibilities

The expression has a clear inside-then-outside structure thanks to the parentheses, so Tool #7 (Identify Subproblems) is the natural fit: first compute the inner $5 \, \blacklozenge \, 3$, then plug that result into the outer $\bigstar \, 6$. We treat each unfamiliar symbol like a tiny recipe — read the letters $a$ and $b$, line them up with the actual numbers around the symbol, and substitute. Tool #3 (Eliminate Possibilities) is the AMC multiple-choice safety net: after computing, we check that the value matches one of the five offered choices and that the others can be ruled out, guarding against an arithmetic slip.

Execute — Answer: D

#7 Identify Subproblems 5.OA.A.1 Step 1
  • Split the expression at the parentheses.
  • The whole problem becomes two smaller problems: (i) find $5 \, \blacklozenge \, 3$, (ii) take that number and apply $\bigstar \, 6$ to it.
  • Doing them in this order respects the parentheses.
$$(5 \, \blacklozenge \, 3) \, \bigstar \, 6 \;=\; \big[\,5 \, \blacklozenge \, 3\,\big] \, \bigstar \, 6$$

💡 Reading the parentheses first is the Grade 5 "use parentheses in numerical expressions" rule, and it gives us our two subproblems.

#7 Identify Subproblems 6.EE.A.2 Step 2
  • Apply the $\blacklozenge$ recipe with $a = 5$ and $b = 3$.
  • The rule says $a \, \blacklozenge \, b = a^2 - b^2$, so substitute the numbers into the letters.
$$5 \, \blacklozenge \, 3 \;=\; 5^2 - 3^2$$

💡 Plugging numbers into letters $a$ and $b$ of a defined formula is exactly Grade 6 "evaluate expressions where letters stand for numbers".

#7 Identify Subproblems 6.EE.A.1 Step 3

Carry out the arithmetic: square each number, then subtract.

$$5^2 - 3^2 \;=\; 25 - 9 \;=\; 16$$

💡 Evaluating $5^2$ and $3^2$ uses Grade 6 "whole-number exponents"; the subtraction $25 - 9$ is well-within-grade arithmetic.

#7 Identify Subproblems 6.EE.A.2 Step 4
  • Now substitute the inner result back: the expression has become $16 \, \bigstar \, 6$.
  • Apply the $\bigstar$ recipe with $a = 16$ and $b = 6$, where the rule is $a \, \bigstar \, b = (a-b)^2$.
$$16 \, \bigstar \, 6 \;=\; (16 - 6)^2 \;=\; 10^2 \;=\; 100$$

💡 We reuse the same Grade 6 substitution move on a different defined operation, and the exponent finishes the work.

#3 Eliminate Possibilities 5.OA.A.1 Step 5
  • Match the computed value $100$ against the five answer choices: $-20$, $4$, $16$, $100$, $220$.
  • Only choice (D) hits it; the others can be eliminated.
  • (Notice the trap: $16$ in choice (C) is exactly the intermediate result $5 \, \blacklozenge \, 3$, designed to catch students who stop after the first subproblem.)
$$100 \;\Rightarrow\; \textbf{(D)}$$

💡 Lining the result up against the five choices is the AMC multiple-choice habit and catches the "stopped halfway" trap labelled (C).

[1] #7 5.OA.A.1 Split the expression at the parentheses. The whole problem becomes two smaller p
[2] #7 6.EE.A.2 Apply the $\blacklozenge$ recipe with $a = 5$ and $b = 3$. The rule says $a \, \
[3] #7 6.EE.A.1 Carry out the arithmetic: square each number, then subtract.
[4] #7 6.EE.A.2 Now substitute the inner result back: the expression has become $16 \, \bigstar
[5] #3 5.OA.A.1 Match the computed value $100$ against the five answer choices: $-20$, $4$, $16$

Review

Reasonableness: The two operations both involve squaring, so the final answer should be a non-negative number on the order of $10^2$. We got $100$, which is exactly $10^2$ and lands in the middle of the answer range — perfectly reasonable. We can also sanity-check the trap: choice (C) $16$ is the inner result alone, choice (A) $-20$ would only appear if we accidentally did $a - b^2$ instead of $(a-b)^2$, and choice (E) $220$ is roughly $16^2 - 6^2 = 220$, the answer if someone mistakenly applied $\blacklozenge$ on the outside instead of $\bigstar$. Each distractor maps to a specific misstep, and our path avoids all of them.

Alternative: Tool #9 (Solve an Easier Related Problem): replace the unfamiliar symbols with familiar function names — let $f(a,b) = a^2 - b^2$ and $g(a,b) = (a-b)^2$. The problem becomes $g(f(5,3),\,6)$, a plain composition of two functions. Computing $f(5,3) = 16$ and then $g(16,6) = 100$ gives the same answer (D). This reframing makes the structure feel like the everyday "plug-the-output-of-one-machine-into-another" idea, which is the whole point of defined operations.

CCSS standards used (min grade 6)

  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate (Respecting the parentheses to evaluate the inner $5 \, \blacklozenge \, 3$ before the outer $\bigstar \, 6$, and then matching the final value to the multiple-choice list.)
  • 6.EE.A.1 Write and evaluate numerical expressions involving whole-number exponents (Computing $5^2 = 25$, $3^2 = 9$, and $10^2 = 100$ inside the two defined operations.)
  • 6.EE.A.2 Write, read, and evaluate expressions in which letters stand for numbers (Substituting $a = 5,\, b = 3$ into the $\blacklozenge$ rule $a^2 - b^2$, and $a = 16,\, b = 6$ into the $\bigstar$ rule $(a-b)^2$, just like evaluating an algebraic expression with given variable values.)

⭐ This AMC 8 problem only needs Grade 6 expression evaluation — plug numbers into the letters of a formula — that you already know!

⭐ This AMC 8 problem only needs Grade 6 expression evaluation — plug numbers into the letters of a formula — that you already know!