AMC 10 · 2021 · #5
Grade 5 arithmeticProblem
The ages of Jonie's four cousins are distinct single-digit positive integers. Two of the cousins' ages multiplied together give , while the other two multiply to . What is the sum of the ages of Jonie's four cousins?
Pick an answer.
Toolkit + CCSS Solution
Understand
Restated: Jonie has four cousins whose ages are four different single-digit positive integers (so each age is in $\{1, 2, \dots, 9\}$). One pair of ages multiplies to $24$, the other pair multiplies to $30$. Find the sum of the four ages.
Givens: Four ages are distinct positive integers in $\{1, 2, \dots, 9\}$; Two ages multiply to $24$; The other two ages multiply to $30$; Answer choices: (A) $21$, (B) $22$, (C) $23$, (D) $24$, (E) $25$
Unknowns: The sum of the four ages
Understand
Restated: Jonie has four cousins whose ages are four different single-digit positive integers (so each age is in $\{1, 2, \dots, 9\}$). One pair of ages multiplies to $24$, the other pair multiplies to $30$. Find the sum of the four ages.
Givens: Four ages are distinct positive integers in $\{1, 2, \dots, 9\}$; Two ages multiply to $24$; The other two ages multiply to $30$; Answer choices: (A) $21$, (B) $22$, (C) $23$, (D) $24$, (E) $25$
Plan
Primary tool: #2 Make a Systematic List
Secondary: #3 Eliminate Possibilities
Tool #2 (Systematic List) — list every single-digit factor pair of $24$ in increasing order, then every single-digit factor pair of $30$. The set of pairs is tiny, so listing finishes quickly. Tool #3 (Eliminate) handles the "distinct" constraint: combine each $24$-pair with each $30$-pair, drop any combination that repeats an age, and the survivor is forced.
Execute — Answer: B
4.OA.B.4 Step 1 - List the single-digit factor pairs of $24$.
- Walk from the smallest factor up: $1 \times 24$ (drop, $24$ is two digits), $2 \times 12$ (drop), $3 \times 8$ (keep), $4 \times 6$ (keep).
- So the $24$-pair is $\{3, 8\}$ or $\{4, 6\}$.
💡 List factor pairs in order — Grade 4 "find all factor pairs of a whole number".
4.OA.B.4 Step 2 - List the single-digit factor pairs of $30$.
- $1 \times 30$ (drop), $2 \times 15$ (drop), $3 \times 10$ (drop), $5 \times 6$ (keep).
- Only $\{5, 6\}$ works.
💡 Same factor-pair walk, but here only one pair stays single-digit.
5.OA.B.3 Step 3 - Combine the $24$-pair with $\{5, 6\}$ and drop the case with a repeat.
- Trying $\{4, 6\}$ with $\{5, 6\}$ repeats the $6$ — drop.
- Trying $\{3, 8\}$ with $\{5, 6\}$ gives four distinct ages $\{3, 5, 6, 8\}$ — keep.
💡 "Distinct" forces $6$ out of one side — pick the side that survives.
2.NBT.B.5 Step 4 - Add the four ages.
- $3 + 5 + 6 + 8 = 22$, which is choice (B).
💡 Add four small whole numbers — Grade 2 within-$100$ addition.
4.OA.B.4 List the single-digit factor pairs of $24$. Walk from the smallest factor up: $1 4.OA.B.4 List the single-digit factor pairs of $30$. $1 \times 30$ (drop), $2 \times 15$ 5.OA.B.3 Combine the $24$-pair with $\{5, 6\}$ and drop the case with a repeat. Trying $\ 2.NBT.B.5 Add the four ages. $3 + 5 + 6 + 8 = 22$, which is choice (B). Review
Reasonableness: Double-check the two products: $3 \times 8 = 24$ ✓ and $5 \times 6 = 30$ ✓. All four ages $\{3, 5, 6, 8\}$ are distinct single-digit positive integers ✓. Sum $22$ lies right in the middle of the answer choices $21$–$25$, which is plausible for four ages around $5$–$6$ each.
Alternative: Tool #6 (Guess and Check) — guess the sum directly. The smallest plausible pair is $\{3, 8\}$ summing $11$, and $\{5, 6\}$ summing $11$, so the total is $11 + 11 = 22$ without listing all cases. Same answer (B).
CCSS standards used (min grade 5)
2.NBT.B.5Fluently add and subtract within 100 (Computing $3 + 5 + 6 + 8 = 22$ at the end.)4.OA.B.4Find all factor pairs and recognize multiples; determine prime or composite (Listing every single-digit factor pair of $24$ and of $30$.)5.OA.B.3Generate two numerical patterns using two given rules and identify relationships (Combining each $24$-pair with the $30$-pair and applying the "all distinct" rule to pick the valid set.)
⭐ This AMC 10 problem only needs Grade 5 "list and compare factor pairs" — $24 = 3 \times 8$ or $4 \times 6$, $30 = 5 \times 6$, and the "all distinct" rule forces $\{3, 5, 6, 8\}$ with sum $22$!
⭐ This AMC 10 problem only needs Grade 5 "list and compare factor pairs" — $24 = 3 \times 8$ or $4 \times 6$, $30 = 5 \times 6$, and the "all distinct" rule forces $\{3, 5, 6, 8\}$ with sum $22$!